2log(y)+y^2=4x

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Solution for 2log(y)+y^2=4x equation: 


Simplifying
2log(y) + y2 = 4x

Multiply glo * y
2gloy + y2 = 4x

Solving
2gloy + y2 = 4x

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1y2' to each side of the equation.
2gloy + y2 + -1y2 = 4x + -1y2

Combine like terms: y2 + -1y2 = 0
2gloy + 0 = 4x + -1y2
2gloy = 4x + -1y2

Divide each side by '2loy'.
g = 2l-1o-1xy-1 + -0.5l-1o-1y

Simplifying
g = 2l-1o-1xy-1 + -0.5l-1o-1y

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